dy/dx+tanx tany=cosx secy
Answer: multiply by cosy and you have
cosy y’ + tanx siny = cosx
Now let u = siny and you have
u’ + tanx u = cosx
That should look more familiar.
dy/dx+tanx tany=cosx secy
Answer: multiply by cosy and you have
cosy y’ + tanx siny = cosx
Now let u = siny and you have
u’ + tanx u = cosx
That should look more familiar.