The reaction yield is 94.4% and there are 4.73 g of magnesium with 1.83 g of water in the reaction. Mg (24 amu): H (1 amu): 0
(16 amu):
Mg(s) + 2H20 (1) >Mg(OH)2 (s) + H2(g)
Blank 1 how many moles of Mg in 4.73 g Mg?
Blank 2 how many moles of H20 in 1.83 g H2O?
Blank 3 which is the limiting molecule?
Blank 4 what mass in grams of hydrogen is produced?
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