The Question : Two tangents TP and TQ are drawn to a circle with centre O from an external point T. Prove that ∠PTQ = 2∠OPQ
Solution for the question :
Let ∠PTQ = θTPQ is an isosceles triangle. ∠TPQ = ∠TQP = 1/2 (1800 − θ) = 900 − θ/2 ∠OPT = 900 ∠OPQ = ∠OPT − ∠TPQ = 900 − (900 − θ/2 ) = θ/2 ∠OPQ = 1/2 ∠PTQ 2∠OPQ = ∠PTQ
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