The Question : From a point P, two tangents PA and PB are drawn to a circle C(0, r). If OP = 2r, then find ∠AP
B) What type of triangle is APB?
Solution for the question :
let ∠APO = θSinθ = OA/ OP = 1/2 ⇒ = 300 ⇒ ∠APB = 2θ = 600 Also ∠PAB = ∠PBA = 600 (∵ PA=PB )⇒△ APB is equilateral
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