The Question : Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
| Distance (in m) | 0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
| Number of Students | 40 | 80 | 62 | 38 | 30 |
Solution for the question :
Solution:Distance (in m)0-11-22-33-44-5Number of Students4080623830cf40120182220250n/2=250/2= 125 ⇒ median class is 2 − 3, l = 2, h = 1, cf = 120, f = 62median =l+(n/2-cf/f)×h= 2+ (125-120/62) × 1= 2 + 5/62 = 129/62 = 2.08 m 50% of students jumped below 2.08 m and 50% above it.
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