The Question : A boy 1.7 m tall is standing on a horizontal ground, 50 m away from a building. The angle of elevation of the top of the building from his eye is 60°. Calculate the height of the building. (Take √3 = 1.73)
Solution for the question :
Solution:Let PR be the building and AB be the boy In ∆PQR, tan600 = PQ/50 ⇒ √3 = PQ/50⇒ PQ = 50√3m Height of the building = PR = PQ + QR= (50√3 + 1.7)m = 88.2m
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